Posted by **Ian** on Sunday, September 5, 2010 at 5:32pm.

Suppose that you are at the top of a (rigid) rocket which is half a light

year tall. If the rocket is accelerating such that your proper acceleration

is 1g,

What is the proper acceleration at the bottom of the rocket?

B =

F c2

c2 F

:

This is one of the equations given:

alpha B = (alpha f c^2)/(c^2 - delta alpha f)

It seems that delta alpha f is the difference in accelerations. I can't find any equation that uses the distance. Is it OK to use the distance in this one?

## Answer This Question

## Related Questions

- Physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...
- Physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...
- Physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - A small weather rocket weighs 14.7 N. The rocket is carried up by a ...
- Physics - Consider a rocket in space that ejects burned fuel at a speed of vex= ...
- Physics - A 5.00×10^5-kg rocket is accelerating straight up. Its engines produce...

More Related Questions