If someone could point me in the right direction-please!!!
A car with an initial speed of 4.30m/s accerlerates uniformly at the rate of 3.00 m/s ^2. Find final speed after 5.00s.
Thanks for any help you can provide.
Acc. = (Vt - Vo) / t
3m/s^2 = (Vt - 4.3m/s) / 5.0s,
3 = (Vt - 4.3) / 5,
Cross multiply:
Vt - 4.3 = 15,
Vt = 19.3m/s
To find the final speed of the car after 5.00 seconds, you can use the kinematic equation:
vf = vi + at
Where:
vf is the final velocity,
vi is the initial velocity,
a is the acceleration, and
t is the time.
In this case, the initial velocity (vi) is given as 4.30 m/s, the acceleration (a) is 3.00 m/s^2, and the time (t) is 5.00 seconds.
Plugging these values into the equation, we get:
vf = 4.30 m/s + (3.00 m/s^2 * 5.00 s)
Calculating the acceleration multiplied by time first:
vf = 4.30 m/s + 15.00 m/s
Finally, adding the initial velocity and the result of the previous calculation:
vf = 19.30 m/s
Therefore, the final speed of the car after 5.00 seconds is 19.30 m/s.