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Math

posted by on .

x = 3

-2x^(2) / (1/3)^(-x)

how to solve?

would I multiply 3(-2) than square?
Also, when I move (1/3)^(-3) to the numerator would it become (3)^3

  • Math - ,

    -2x^(2) / (1/3)^(-x)
    when x = 3 I get

    -2(9)/(1/3)^-3
    = -18(1/3)^+3
    = -18(1/27)
    = -2/3

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