Posted by Nikki on Sunday, September 5, 2010 at 12:56pm.
This is a good Calculus question.
label your diagram as follows
A - position of boat
B - point on shore closest to A
C- point on shore where he should row to (our answer)
V - position of the village
Clearly ABC is a right angle,
let BC = x, then CV = 6-x
AB = 2
AC = √(x^2 + 4)
Time in water = √(x^2 + 4)/2
time along shore = (6-x)/5
Time = (1/2)(x^2 + 4)^(1/2) + 6/5 - x/5
dTime/dx = (1/4)(x^2+4)^(-1/2)(2x) - 1/5
set this equal to zero and solve for x
let me know what you got.
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