Posted by **jessica** on Sunday, September 5, 2010 at 11:16am.

(a minus sqrtx)^2=25

I have no idea of how to work this problem where i in up with the answers of a=7,-3. Basiclly I just gave it a guess. Could someone show the steps I need to take. Thanks.

- algebra -
**bobpursley**, Sunday, September 5, 2010 at 11:34am
take the sqrt of each side.

a-sqrtx=+- 5

now work each possible sign

sqrtx=a-5 or sqrt x=a+5

then square each side:

x=(a-5)^2 or x=(a+5)^2

Now you are presented with a quandry, resolve this way. If the domain of x is restricted to real numbers, then you cant take a sqrt of a negative numer, so

x>= 0 which means

(a-5)>0 or a>5 and (a+5)>0 a>-5 but the first predominates, so a>5 is the restriction on a.

- algebra -
**Trina**, Sunday, September 5, 2010 at 12:04pm
what happen the the results of a=7, -3 to this problem because when I plug them in it equal to 25 in the end. Could you explain this a little more for me. Thanks.

## Answer this Question

## Related Questions

- algebra 1 - Can someone please help me with this inequality problem -3-8>(4x+...
- math - Could someone show me how to solve this problem? I am trying to do it ...
- algebra ll - i answersd this question and i got it wrong i dont know why if you ...
- algebra ll - i answersd this question and i got it wrong i dont know why if you ...
- Algebra - If (x+2)² = 25 and x > 0, what is the value of x? I have no idea ...
- fractions - my teacher gave us some fraction problems for homework, but I'm ...
- Algebra 2 - Helllo I have no idea how to do this problem given f(x) = x-3(x + 4...
- Algebra - I have never had algebra and cannot figure out how to work through the...
- math, beginning algebra - how do i solve the following equations. Problem # 1 3x...
- algebra 1 - I was just wondering if anybody could explain to me the steps in '...

More Related Questions