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November 21, 2014

November 21, 2014

Posted by **jen** on Saturday, September 4, 2010 at 2:02pm.

- algebra -
**Henry**, Saturday, September 4, 2010 at 7:49pm2x^2 - 3x + 6 = 0.

x = 3+- sqrt(9 - 48) / 4 =

3 +- sqrt(-39) / 4 =

(3 +- sqrt(39*-1)) / 4

sqrt(-1) = i

x = +- isqrt(39) / 4

Solution Set:

x =(3 - isqrt(39)) / 4

x =(3 + isqrt(39)) / 4

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