algebra
posted by jen on .
use the quadratic formula to solve the equation 2x^23x=6

2x^2  3x + 6 = 0.
x = 3+ sqrt(9  48) / 4 =
3 + sqrt(39) / 4 =
(3 + sqrt(39*1)) / 4
sqrt(1) = i
x = + isqrt(39) / 4
Solution Set:
x =(3  isqrt(39)) / 4
x =(3 + isqrt(39)) / 4