Posted by **Shaila** on Saturday, September 4, 2010 at 11:16am.

Car A, with mass of 1735kg, was traveling north at 45.5km/h and car B, with a mass of 2540kg, was traveling west at 37.7km/h when they collided at an intersection. if the cars stuck together after the collision, what was their combined momentum? Was the collision elastic or inelastic?

- Physics - elastic collision -
**bobpursley**, Saturday, September 4, 2010 at 1:25pm
It is NOT an elastic collision, they stuck together. Combined momentum= sum of initial momentums. Do this as vector addition.

- Physics - elastic collision -
**Shaila**, Monday, September 13, 2010 at 2:15pm
Since the directions are north and west you directly use the Pythagoras theorem to find the resultant speed?? and the tan of the two two get the angle??

- Physics - elastic collision -
**Anonymous**, Friday, October 28, 2011 at 1:10pm
Given:

Mass of Car a (Ma)= 1735kg, Vai= 45.5 km/hour= 12.64m/s

Mass of Car b (Mb) = 2540kg, Vbi= 37.7km/hour= 10.47m/s

pi = pf

MaVai+ MbVbi = Vf (m1+m2)

(175)(12.64) + (2540)(10.47) = pf

pf = 28805.8 J

Elastic collision because Pi=Pf

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