Homework Help: calculus

Posted by Jin on Saturday, September 4, 2010 at 12:05am.

Consider the function

f(x)=–3x3–1x2+1x+1Find the average slope of this function on the interval (–2–1).
By the Mean Value Theorem, we know there exists a c in the open interval (–2–1) such that f(c) is equal to this mean slope. Find the value of c in the interval which works

I found the mean which is -17 but I can't get the C. I don't know what im doing wrong

calculus - Damon, Saturday, September 4, 2010 at 4:23am
f(-1) = 3-1-1+1 = 2
f(-2) = 19
slope = (2-19)/1 = -17 agree

f'(x) = -9 x^2 - 2 x + 1
for what values of x is that -17?
-9 x^2 - 2 x + 1 = -17

9 x^2 + 2 x - 18 = 0

x = [-2 +/- sqrt (4+648)]/18
= 1.3 or -1.53

-1,53 is in the domain

check it by calculating
f'(1.53)

Answer this Question

Related Questions

calculus - Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the ...
calculus - Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. ...
CALCULUS! - Consider the function f(x)=4x^3–2x on the interval [–2,2...
calculus - Consider the function f(x)=6sqrt(x)+1 on the interval [3,5] . Find ...
calc - consider the function f(x)=x^3 - x^2 - 3x -2. find the average slope of ...
Calc, Mean Value Theorem - Consider the function : 3x^3 - 2x^2 - 4x + 1 Find the...
Calculus - Find the average or mean slope of 2x^3 - 6x^2 - 90x +3 on the ...
math - Consider the function f(x)=10sqrrootx+5 on the interval [3,10]. i found ...
Math - Consider the function f(x)=8(x^(1/2))+7 on the interval [1,5]. By the ...
Calculus - Verify the hypothesis of the mean value theorem for each function ...

For Further Reading

First Name:
School Subject:
Answer: