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March 5, 2015

March 5, 2015

Posted by **Jin** on Saturday, September 4, 2010 at 12:05am.

f(x)=–3x3–1x2+1x+1Find the average slope of this function on the interval (–2–1).

By the Mean Value Theorem, we know there exists a c in the open interval (–2–1) such that f(c) is equal to this mean slope. Find the value of c in the interval which works

I found the mean which is -17 but I can't get the C. I don't know what im doing wrong

- calculus -
**Damon**, Saturday, September 4, 2010 at 4:23amf(-1) = 3-1-1+1 = 2

f(-2) = 19

slope = (2-19)/1 = -17 agree

f'(x) = -9 x^2 - 2 x + 1

for what values of x is that -17?

-9 x^2 - 2 x + 1 = -17

9 x^2 + 2 x - 18 = 0

x = [-2 +/- sqrt (4+648)]/18

= 1.3 or -1.53

-1,53 is in the domain

check it by calculating

f'(1.53)

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