Post a New Question

calculus

posted by on .

Consider the function

f(x)=–3x3–1x2+1x+1Find the average slope of this function on the interval (–2–1).
By the Mean Value Theorem, we know there exists a c in the open interval (–2–1) such that f(c) is equal to this mean slope. Find the value of c in the interval which works

I found the mean which is -17 but I can't get the C. I don't know what im doing wrong

  • calculus - ,

    f(-1) = 3-1-1+1 = 2
    f(-2) = 19
    slope = (2-19)/1 = -17 agree

    f'(x) = -9 x^2 - 2 x + 1
    for what values of x is that -17?
    -9 x^2 - 2 x + 1 = -17

    9 x^2 + 2 x - 18 = 0

    x = [-2 +/- sqrt (4+648)]/18
    = 1.3 or -1.53

    -1,53 is in the domain

    check it by calculating
    f'(1.53)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question