Posted by Ana on Friday, September 3, 2010 at 8:55pm.
how do i solve for y in the equation -5y(6y - 6) - y = -4(y - 5)
- 10th grade math - Reiny, Friday, September 3, 2010 at 9:25pm
-5y(6y - 6) - y = -4(y - 5)
-30y^2 + 30y - y = -4y + 20
30y^2 - 33y + 20 = 0
y = (22 ± √-1311)/60
(22 ± i √1311)/60 , two complex roots.
- 10th grade math - danny, Monday, May 23, 2011 at 8:27pm
how kan i solve this equation
Answer This Question
More Related Questions
- 10th grade math - solve each equation for y. do x and y vary directly? if so ...
- 10th grade algebra - solve the equation 2a=3a+4c for a
- 10th grade algebra - solve the equation 2x+y=9 for y
- 10th grade algebra - solve the equation for x: 3x+y=6
- 10th grade math help - How do you solve? 3-3sinx-2cos^2(x) = 0
- 10th Grade Chemistry - I struggle in the sciences and was wondering what I could...
- 10th grade math - how to solve triangles with parrellel lines running through ...
- 10th grade - BC=3x+2 and CD= 5x-10. Solve for x.
- 10th grade - -8(-3-4 v)+5(5v+2)=-80 solve for v
- 10th grade - what classes should i take in 10th grade?