10th grade math
posted by
Ana on
.
how do i solve for y in the equation 5y(6y  6)  y = 4(y  5)

10th grade math 
Reiny,
5y(6y  6)  y = 4(y  5)
30y^2 + 30y  y = 4y + 20
30y^2  33y + 20 = 0
y = (22 ± √1311)/60
or
(22 ± i √1311)/60 , two complex roots.

10th grade math 
danny,
how kan i solve this equation
7a3a+2aa=16