Posted by mi on Friday, September 3, 2010 at 7:12pm.
Using algebra:
Let x=number of flared skirts,
then 20-x = number of straight skirts
1.5x+1.25(20-x) ≤ 28.25
0.25x ≤ 28.25-20*1.25
x ≤ 3.25/0.25
x ≤ 13
There he can make 13 flared skirts and 7 straight skirts.
Using arithmetic:
If he made all flared skirts, he would need 20*1.5=30 yards.
For every switch he makes, he saves (1.5-1.25)=0.25 yd
Therefore he has to switch (30-28.25)/0.25=7 skirts.
He needs to make 13 flared skirts and 7 straight skirts.
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