Homework Help: physics

Posted by Kellsey on Friday, September 3, 2010 at 3:47pm.

Three charges are fixed to an x, y coordinate system. A charge of +20 湣 is on the y axis at y = 2.7 m. A charge of -14 湣 is at the origin. Last, a charge of +46 湣 is on the x axis at x = +2.7 m. Determine the magnitude and direction of the net electrostatic force on the charge at x = +2.7 m. Specify the direction relative to the −x axis.

physics - bobpursley, Friday, September 3, 2010 at 4:12pm
First,find the force from each of the other charges:

Force at-45 degrees: k20*46*E-12/(2.7)^2

Force at 180 degrees: k20*14E-12/2.7^2

now break up the first force into -y,x components:
force in 0 deg (x): 20k*46E-12/2.7^2 *.707

force in -y : k20*46E-12/(2.7^2) * .707

net force in x direction:
k20*46/2.7^2 (.707-14/20)=zero check that.

Net force then is in -y direction, as given above.
physics - Happy Face, Friday, September 3, 2010 at 5:44pm
wow lol XD
physics - Rodney, Friday, May 11, 2012 at 3:12am
what is the net electrostatic force on the charge q3 -48駥 due to charges q1 (+78湣) and q2 (+50湣)

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