# physics

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Three charges are fixed to an x, y coordinate system. A charge of +20 µC is on the y axis at y = 2.7 m. A charge of -14 µC is at the origin. Last, a charge of +46 µC is on the x axis at x = +2.7 m. Determine the magnitude and direction of the net electrostatic force on the charge at x = +2.7 m. Specify the direction relative to the −x axis.

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First,find the force from each of the other charges:

Force at-45 degrees: k20*46*E-12/(2.7)^2

Force at 180 degrees: k20*14E-12/2.7^2

now break up the first force into -y,x components:
force in 0 deg (x): 20k*46E-12/2.7^2 *.707

force in -y : k20*46E-12/(2.7^2) * .707

net force in x direction:
k20*46/2.7^2 (.707-14/20)=zero check that.

Net force then is in -y direction, as given above.

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wow lol XD

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what is the net electrostatic force on the charge q3 -48ìc due to charges q1 (+78µC) and q2 (+50µC)

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A point charge of +5µC is on the axis at y = 3cm, and a second point charge of -6µC is on the axis at y = -3cm. Where a third charge of +2µC should be placed so that the system is in equilibrium?