as the shuttle bus comes to a sudden stop to aboid hitting a dog, it sccelerates uniformly at -4.1 m/s^2 as it slows from 9.0 m/s to 0 m/s. find the time intercal of acceleration for the bus.
Actually, it is decelerating at a rate of 4.1 m/s^2. The time required = (initial speed)/(deceleration rate)
= 9.0/4.1 = ___ s
To find the time interval of acceleration for the bus, we can use the equation of motion:
v = u + at
Where:
v = final velocity (0 m/s)
u = initial velocity (9.0 m/s)
a = acceleration (-4.1 m/s^2)
t = time interval
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (0 - 9.0) / (-4.1)
t = -9.0 / -4.1
t ≈ 2.20 seconds
Therefore, the time interval of acceleration for the bus is approximately 2.20 seconds.