I have a test tommorow and I forgot how to do this:
Caculate mass of Cr in 548g of K2Cr2O7.
I remember putting 548g K2Cr2O7 (1 mol K2Cr2O7/294.2 g K2Cr2O7) then from there I forgot.
I got 96.85 g Cr but that does not seem right.
Could someone please tell me the steps
I figured it out
To calculate the mass of Cr in 548g of K2Cr2O7, you need to use stoichiometry and molar ratios.
Here are the steps to calculate it correctly:
Step 1: Start by writing down the balanced chemical equation for the reaction involving K2Cr2O7:
2 K2Cr2O7 → 2 K2CrO4 + Cr2O3 + O2
Step 2: Determine the molar mass of K2Cr2O7 and Cr:
- The molar mass of K2Cr2O7 is 294.2 g/mol
- The molar mass of Cr is 52 g/mol
Step 3: Use the given information and the balanced equation to set up a conversion factor:
548g K2Cr2O7 * (1 mol K2Cr2O7/294.2 g K2Cr2O7)
Step 4: Simplify the conversion factor by canceling out units:
548g K2Cr2O7 * (1 mol K2Cr2O7/294.2 g K2Cr2O7) * (1 mol Cr/2 mol K2Cr2O7) * (52 g Cr/1 mol Cr)
Step 5: Calculate the mass of Cr:
548g K2Cr2O7 * (1/294.2) * (1/2) * (52) = 96.85 g Cr
So your calculation of 96.85 g Cr is correct. It seems that your answer is accurate based on the given information and calculations.