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I have a test tommorow and I forgot how to do this:

Caculate mass of Cr in 548g of K2Cr2O7.

I remember putting 548g K2Cr2O7 (1 mol K2Cr2O7/294.2 g K2Cr2O7) then from there I forgot.

I got 96.85 g Cr but that does not seem right.

Could someone please tell me the steps

  • Chemistry - ,

    I figured it out

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