posted by Amy~ on .
I have a test tommorow and I forgot how to do this:
Caculate mass of Cr in 548g of K2Cr2O7.
I remember putting 548g K2Cr2O7 (1 mol K2Cr2O7/294.2 g K2Cr2O7) then from there I forgot.
I got 96.85 g Cr but that does not seem right.
Could someone please tell me the steps
I figured it out