Vectors
posted by Victor on .
Given the vectors below, determine the resultant and the equilibrant using trigonometry. Show all your steps.
330.0 newtons @ 125 degrees
250.0 newtons @ 60.0 degrees

Fr = 330[125o] + 250[60o] = Resultant force.
X = 330*Cos125 + 250*Cos60 = 64.3 N.
Y = 330*sin125 + 250*sin60 = 487 N.
Q2.
Tan A = Y/X = 487/64.3 = 7.57387.
A = 82.5o = 82.5o N. of W. = 97.5o CCW.
Fr=Y/sin A = 487/sin97.5 = 491 N.[97.5o}
Fr + Fe = 0, Fe = Fr.
Fe = (64.3 + 487i) = 64.3  487i =
491[82.5o] S. of E. = 491 N.[277.5o]CCW.
= Equilibrant force.
Or Fe=Fr=Fr[97.5o+180o] = 491N.[277.5]