Posted by **Victor** on Thursday, September 2, 2010 at 1:06pm.

Given the vectors below, determine the resultant and the equilibrant using trigonometry. Show all your steps.

330.0 newtons @ 125 degrees

250.0 newtons @ 60.0 degrees

- Vectors -
**Henry**, Friday, October 23, 2015 at 5:03pm
Fr = 330[125o] + 250[60o] = Resultant force.

X = 330*Cos125 + 250*Cos60 = -64.3 N.

Y = 330*sin125 + 250*sin60 = 487 N.

Q2.

Tan A = Y/X = 487/-64.3 = -7.57387.

A = -82.5o = 82.5o N. of W. = 97.5o CCW.

Fr=Y/sin A = 487/sin97.5 = 491 N.[97.5o}

Fr + Fe = 0, Fe = -Fr.

Fe = -(-64.3 + 487i) = 64.3 - 487i =

491[82.5o] S. of E. = 491 N.[277.5o]CCW.

= Equilibrant force.

Or Fe=-Fr=Fr[97.5o+180o] = 491N.[277.5]

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