I have 2 questions:

Assuming that water has a density of exactly 1 g/cm3, find the mass of one cubic meter of water in kilograms.

Suppose that it takes 10.0 h to drain a container of 5700m3 of water. What is the "mass flow rate," in kilograms per second, of water from the container.

Thanks!!

for the first question,

there is 1g of water per 1 cm cube

therefore there is 1000 kg of water per 1 m cube

that is your answer

for the 2nd one, im not sure

Sure! Let's tackle your first question:

To find the mass of one cubic meter of water in kilograms, we need to use the given density of water, which is 1 g/cm^3.

To convert the units from grams per cubic centimeter to kilograms per cubic meter, we can use the following conversion factors:

1 gram = 0.001 kilograms (since there are 1000 grams in a kilogram)
1 cubic centimeter (cm^3) = 0.000001 cubic meters (m^3) (since there are 1,000,000 cubic centimeters in a cubic meter)

So, to convert from grams per cubic centimeter to kilograms per cubic meter, we multiply the given density by these conversion factors:

1 g/cm^3 * 0.001 kg/g * 0.000001 m^3/cm^3 = 0.001 kg/m^3

Therefore, the mass of one cubic meter of water is 0.001 kilograms.

Now let's move on to your second question:

To find the mass flow rate of water from the container in kilograms per second, we need to divide the total mass of water by the time it takes to drain the container.

Given:
Volume of water = 5700 m^3
Time taken = 10.0 hours = 10.0 * 3600 seconds (since there are 3600 seconds in an hour)

To find the mass flow rate, we need the mass of water, which we can calculate using the density:

Mass = Density * Volume
Mass = 0.001 kg/m^3 * 5700 m^3
Mass = 5.7 kg

Now, divide the mass by the time taken:

Mass Flow Rate = Mass / Time
Mass Flow Rate = 5.7 kg / (10.0 * 3600) s
Mass Flow Rate ≈ 0.0001583 kg/s

Therefore, the mass flow rate of water from the container is approximately 0.0001583 kilograms per second.