Posted by Katie S on Wednesday, September 1, 2010 at 4:08pm.
domain is your choice of x's you can use
First of all the bottom cannot be zero
so
x^2 - 2x - 15 ≠ 0
(x-5)(x+3) ≠ 0
x≠5 or x≠ -3
Secondly the entire expression cannot be negative, because of the square root part
it simplifies to
(x+8)(x-2)/((x-5)(x+3)
clearly any x<-8 and x> 5 are ok
also the expression is positive between -3 and 2
it is negative between -8 and -3, as well as 2 to 5
I will let let you summarize the above.
Make a number line , put those critical values on and mark the line accordingly
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