Posted by **Shaila** on Wednesday, September 1, 2010 at 6:07am.

Two cars of identical mass are approaching the same intersection, one from the south and the one from the west. They reach the intersection at the same time and collide. The cars lock together and move away at an angle of 22deg counterclockwise from the road; heading east. Which car was traveling faster than the other before the collision? Explain your reasoning

- Physics - Momentum of cars at intersection -
**drwls**, Wednesday, September 1, 2010 at 7:08am
The momentum component of the combined cars in the eastern direction exceeds the component in the north-traveling direction. Therefore most of the momentum came from the east-traveling car. The ratio is cos22/sin22 = 2.475

Assuming the cars had about the same mass, the east-traveling car had the higher original speed.

- Physics - Momentum of cars at intersection -
**moza**, Thursday, January 6, 2011 at 3:49am
Two vehicles are approaching an intersection. One is a 2500-

kg pickup traveling at 14.0 m/s from east to west (the negative x-direction),

and the other is a 1500-kg Mercedes going from south to north (the positive

y-direction at 23.0 m/s). (a) Find the x and y components of the net

momentum of this system. (b) What are the magnitude and direction of the

net momentum?

- physics -
**Qais**, Sunday, January 9, 2011 at 5:32am
m1v1v+m2v2=(m1+m2)V

2500*-14i+1500*23j=(3800)V

then X-comp is 2500*-14/3800

Y-comp is 1500*23/3800

P=(m1+m2)V

find the value of V from the square root of the previous ....

0553053359

- Physics - Momentum of cars at intersection -
**what?**, Thursday, December 6, 2012 at 12:50am
Is this in english?

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