Posted by Shaila on Wednesday, September 1, 2010 at 6:07am.
Two cars of identical mass are approaching the same intersection, one from the south and the one from the west. They reach the intersection at the same time and collide. The cars lock together and move away at an angle of 22deg counterclockwise from the road; heading east. Which car was traveling faster than the other before the collision? Explain your reasoning

Physics  Momentum of cars at intersection  drwls, Wednesday, September 1, 2010 at 7:08am
The momentum component of the combined cars in the eastern direction exceeds the component in the northtraveling direction. Therefore most of the momentum came from the easttraveling car. The ratio is cos22/sin22 = 2.475
Assuming the cars had about the same mass, the easttraveling car had the higher original speed.

Physics  Momentum of cars at intersection  moza, Thursday, January 6, 2011 at 3:49am
Two vehicles are approaching an intersection. One is a 2500
kg pickup traveling at 14.0 m/s from east to west (the negative xdirection),
and the other is a 1500kg Mercedes going from south to north (the positive
ydirection at 23.0 m/s). (a) Find the x and y components of the net
momentum of this system. (b) What are the magnitude and direction of the
net momentum?

physics  Qais, Sunday, January 9, 2011 at 5:32am
m1v1v+m2v2=(m1+m2)V
2500*14i+1500*23j=(3800)V
then Xcomp is 2500*14/3800
Ycomp is 1500*23/3800
P=(m1+m2)V
find the value of V from the square root of the previous ....
0553053359

Physics  Momentum of cars at intersection  what?, Thursday, December 6, 2012 at 12:50am
Is this in english?
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