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Posted by **Shaila** on Wednesday, September 1, 2010 at 6:07am.

- Physics - Momentum of cars at intersection -
**drwls**, Wednesday, September 1, 2010 at 7:08amThe momentum component of the combined cars in the eastern direction exceeds the component in the north-traveling direction. Therefore most of the momentum came from the east-traveling car. The ratio is cos22/sin22 = 2.475

Assuming the cars had about the same mass, the east-traveling car had the higher original speed.

- Physics - Momentum of cars at intersection -
**moza**, Thursday, January 6, 2011 at 3:49amTwo vehicles are approaching an intersection. One is a 2500-

kg pickup traveling at 14.0 m/s from east to west (the negative x-direction),

and the other is a 1500-kg Mercedes going from south to north (the positive

y-direction at 23.0 m/s). (a) Find the x and y components of the net

momentum of this system. (b) What are the magnitude and direction of the

net momentum?

- physics -
**Qais**, Sunday, January 9, 2011 at 5:32amm1v1v+m2v2=(m1+m2)V

2500*-14i+1500*23j=(3800)V

then X-comp is 2500*-14/3800

Y-comp is 1500*23/3800

P=(m1+m2)V

find the value of V from the square root of the previous ....

0553053359

- Physics - Momentum of cars at intersection -
**what?**, Thursday, December 6, 2012 at 12:50amIs this in english?

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