Physics  Momentum of cars at intersection
posted by Shaila on .
Two cars of identical mass are approaching the same intersection, one from the south and the one from the west. They reach the intersection at the same time and collide. The cars lock together and move away at an angle of 22deg counterclockwise from the road; heading east. Which car was traveling faster than the other before the collision? Explain your reasoning

The momentum component of the combined cars in the eastern direction exceeds the component in the northtraveling direction. Therefore most of the momentum came from the easttraveling car. The ratio is cos22/sin22 = 2.475
Assuming the cars had about the same mass, the easttraveling car had the higher original speed. 
Two vehicles are approaching an intersection. One is a 2500
kg pickup traveling at 14.0 m/s from east to west (the negative xdirection),
and the other is a 1500kg Mercedes going from south to north (the positive
ydirection at 23.0 m/s). (a) Find the x and y components of the net
momentum of this system. (b) What are the magnitude and direction of the
net momentum? 
m1v1v+m2v2=(m1+m2)V
2500*14i+1500*23j=(3800)V
then Xcomp is 2500*14/3800
Ycomp is 1500*23/3800
P=(m1+m2)V
find the value of V from the square root of the previous ....
0553053359 
Is this in english?