Posted by Shaila on Wednesday, September 1, 2010 at 6:07am.
The momentum component of the combined cars in the eastern direction exceeds the component in the north-traveling direction. Therefore most of the momentum came from the east-traveling car. The ratio is cos22/sin22 = 2.475
Assuming the cars had about the same mass, the east-traveling car had the higher original speed.
Two vehicles are approaching an intersection. One is a 2500-
kg pickup traveling at 14.0 m/s from east to west (the negative x-direction),
and the other is a 1500-kg Mercedes going from south to north (the positive
y-direction at 23.0 m/s). (a) Find the x and y components of the net
momentum of this system. (b) What are the magnitude and direction of the
net momentum?
m1v1v+m2v2=(m1+m2)V
2500*-14i+1500*23j=(3800)V
then X-comp is 2500*-14/3800
Y-comp is 1500*23/3800
P=(m1+m2)V
find the value of V from the square root of the previous ....
0553053359
Is this in english?
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