Posted by **Connor** on Tuesday, August 31, 2010 at 7:27pm.

7x^3-24x^2-19x+12

-----------------=f(x)

2x^3-4x^2-40x+80

Determine all values of x for which f is not defined.

- Pre Calc -
**Dave**, Tuesday, August 31, 2010 at 7:55pm
thats supposed to be a fraction all equel to f(x).

- Pre Calc -
**Reiny**, Tuesday, August 31, 2010 at 8:20pm
A function is not defined if the denominator is zero

So we just have to look at the bottom which I will assume is

2x^3 - 4x^2 - 40x + 80

by grouping

= 2x^2(x-2) - 40(x-2)

= (x-2)(2x^2 - 40)

so x-2 cannot be zero, or x ≠ 2

or

2x^ - 40 ≠ 0

x^2 ≠ 20

x ≠ ±√20 or ±2√5

so x ≠ 2, 2√5, -2√5

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