A car traveling 89 strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.81 .

a.)What was the average acceleration of the driver during the collision?

b.)Express the answer in terms of "'s," where .

The cart of mass 10kg moves without frictional loss on a level table. A 10 N force pulls on the cart horizontally to the right. At the same time, a 30N force at an angle of 60 degrees above the horizontal pulls on the cart to the left. What is the magnitude of the horizontal acceleration of the cart?

To find the average acceleration of the driver during the collision, we can use the equation for average acceleration:

Average Acceleration = (Final Velocity - Initial Velocity) / Time

In this case, the car's initial velocity is 89 m/s (given in the question) and the final velocity is 0 m/s (since the driver comes to rest). The time taken to come to rest is given as 0.81 seconds in the question.

a.) Now, we can substitute these values into the formula:

Average Acceleration = (0 m/s - 89 m/s) / 0.81 s

To calculate this, we subtract 89 m/s from 0 m/s and then divide it by 0.81 seconds. Note that the answer will be negative since the car decelerates (slows down).

b.) Expressing the answer in terms of "'s" means expressing it in a simplified form using units of measurement. In this case, the unit of acceleration is m/s^2 (meters per second squared) and there is no specific conversion to "'s". So, the answer to part (a) would be expressed as:

Average Acceleration = -109.88 m/s^2

Thus, the average acceleration of the driver during the collision is -109.88 m/s^2.