Posted by Madison on Tuesday, August 31, 2010 at 9:32am.
Mike's rate = 1/3 lawn/hr
Paul's rate = 1/2 lawn/h
combined rate = (1/3 + 1/2) lawn/hr
= 5/6 lawn/hr
time for combined rate = 1/(5/6) hours
= 6/5 hours
Their answer is wrong.
How can it take 20/9 or more than 2 hours for both of them to do it, when Paul alone could do it in 2 hours.
6/5hrs
t = 3*2 / (3+2) = 6/5 hrs.
Related Questions
smith - tom can mow a lawn in 4 hours. perry can mow the same lawn in 5 hours. ...
algebra - Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn ...
algebra - Bob mosw his lawn in 3 hours, Jane can mow the same lawn in 5 hours. ...
algebra - it john 4 hours to mow a lawn it takes maria 3 hours to mow the same ...
Math - if jack can mow his lawn in 4 hours and sue can mow the same lawn in 7 ...
Math - if jack can mow his lawn in 4 hours and sue can mow the same lawn in 7 ...
Math - if jack can mow his lawn in 4 hours and sue can mow the same lawn in 7 ...
math - Jack usually mows his lawn in 4 hours. Marilyn can mow the same in 5 ...
math/117 - Jack usually mowes his lawn in 7 hours. Marilyn can mow the same yard...
Math - Jack usually mows his lawn in three hours. Marilyn can mow the same yard ...
For Further Reading
