Posted by **James** on Monday, August 30, 2010 at 10:43pm.

Can someone please tell me what the vertex and line of symentry would be for r(x)=-3(x+3)^2.. Thank you

- Math -
**Henry**, Wednesday, September 1, 2010 at 8:10pm
F(x) = y = -3(x + 3)^2 + k.

Vertex Form:

y = a(x - h)^2 + k.

V(h , k) = V(-3 , 0),

Line of sym = h = -3 = Xv.

h is positive in your Eq because you are subtracting a negative 3.

If you gave me the complete Eq, k = 0.

The graph opens downward since a is negative(-3).

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