Saturday

April 19, 2014

April 19, 2014

Posted by **James** on Monday, August 30, 2010 at 10:43pm.

- Math -
**Henry**, Wednesday, September 1, 2010 at 8:10pmF(x) = y = -3(x + 3)^2 + k.

Vertex Form:

y = a(x - h)^2 + k.

V(h , k) = V(-3 , 0),

Line of sym = h = -3 = Xv.

h is positive in your Eq because you are subtracting a negative 3.

If you gave me the complete Eq, k = 0.

The graph opens downward since a is negative(-3).

**Related Questions**

Math 10 - 1 more question.... how would I make this equation perpendicular? The ...

geometry - Trisha drew a pair of line segments starting from a vertex. Which of ...

maths - how do i find out the the equation of the line of symmetry for f(x)=ax^2...

mathematics - Can someone please tell me how to find the vertex for y=x^2-7 ...

Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...

Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...

Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...

Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...

math algebra trig - For the graph of each function, find an equation of the line...

Chemistry - Hi, please can someone tell me if this is the right number of ...