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November 20, 2014

November 20, 2014

Posted by **James** on Monday, August 30, 2010 at 10:43pm.

- Math -
**Henry**, Wednesday, September 1, 2010 at 8:10pmF(x) = y = -3(x + 3)^2 + k.

Vertex Form:

y = a(x - h)^2 + k.

V(h , k) = V(-3 , 0),

Line of sym = h = -3 = Xv.

h is positive in your Eq because you are subtracting a negative 3.

If you gave me the complete Eq, k = 0.

The graph opens downward since a is negative(-3).

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