Posted by **James** on Monday, August 30, 2010 at 10:43pm.

Can someone please tell me what the vertex and line of symentry would be for r(x)=-3(x+3)^2.. Thank you

- Math -
**Henry**, Wednesday, September 1, 2010 at 8:10pm
F(x) = y = -3(x + 3)^2 + k.

Vertex Form:

y = a(x - h)^2 + k.

V(h , k) = V(-3 , 0),

Line of sym = h = -3 = Xv.

h is positive in your Eq because you are subtracting a negative 3.

If you gave me the complete Eq, k = 0.

The graph opens downward since a is negative(-3).

## Answer this Question

## Related Questions

- maths - how do i find out the the equation of the line of symmetry for f(x)=ax^2...
- geometry - Trisha drew a pair of line segments starting from a vertex. Which of ...
- math algebra trig - For the graph of each function, find an equation of the line...
- Math 10 - 1 more question.... how would I make this equation perpendicular? The ...
- Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...
- Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...
- Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...
- Math - The points A(1, -2, 4), B(3, 5, 7), C(4, 6, 8) are three of four vertices...
- mathematics - Can someone please tell me how to find the vertex for y=x^2-7 ...
- Algebra - Identify the vertex and the axis of symmetry for the graph of y=5(x-2...

More Related Questions