Sunday

December 21, 2014

December 21, 2014

Posted by **John** on Monday, August 30, 2010 at 4:32pm.

- Calculus -
**drwls**, Monday, August 30, 2010 at 4:42pmln[(a+b)(a-b)c^8]

= ln[8c(a^2-b^2)]

- Calculus (correction) -
**drwls**, Monday, August 30, 2010 at 4:44pmI overlooked the minus sign.

ln[(a+b)(a-b)/c^8]

= ln[(a^2-b^2)/8c]

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