Sunday
March 26, 2017

Post a New Question

Posted by on .

express the given quantity as a single logarithm: ln(a+b)+ln(a-b)-8ln(c)

  • Calculus - ,

    ln[(a+b)(a-b)c^8]
    = ln[8c(a^2-b^2)]

  • Calculus (correction) - ,

    I overlooked the minus sign.

    ln[(a+b)(a-b)/c^8]
    = ln[(a^2-b^2)/8c]

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question