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posted by John Monday, August 30, 2010 at 4:32pm.

express the given quantity as a single logarithm: ln(a+b)+ln(a-b)-8ln(c)

ln[(a+b)(a-b)c^8] = ln[8c(a^2-b^2)]

I overlooked the minus sign. ln[(a+b)(a-b)/c^8] = ln[(a^2-b^2)/8c]

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