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September 21, 2014

September 21, 2014

Posted by **Lily** on Monday, August 30, 2010 at 9:06am.

Solve: square root of y =(numerator) 5+square root of 2. (Denominator)2

25.5+5square root of 2?

- algebra 1 -
**PsyDAG**, Monday, August 30, 2010 at 9:17amIs this your equation?

y = (5 + √2)/2

Anything divided by 2 would only be half as large.

- algebra 1 -
**Lily**, Monday, August 30, 2010 at 9:37amThe y itself has a square root around it. 5+ square root of 2 is divided by 2.

- algebra 1 -
**Lily**, Monday, August 30, 2010 at 10:13amP.S. There aren't any brackets.

- algebra 1 -
**MathMate**, Monday, August 30, 2010 at 1:56pmThere may not be any brackets explicitly, but whenever there is a numerator, there are implicit brackets around it. The same goes for the denominator.

For example,

Solve: square root of y =(numerator) 5+square root of 2. (Denominator)2

would translate to

√y = (5+√2) / 2

If we omit the brackets, it would become

√y = 5+√2 / 2

which means

√y = 5 + (√2 / 2)

by virtue of the rules of priority of multiplication over addition.

Additional parentheses must be inserted around numerators and denominators in fractions.

Back to your question, assuming the following equation is what you have:

√y = (5+√2) / 2

You can square both sides to give:

y = ±(5+√2)² / 4

=±(25+10√2 + 2)/4

=±(27+10√2)/4

- algebra 1 -
**Lily**, Friday, September 17, 2010 at 8:37amThanks!

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