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September 17, 2014

September 17, 2014

Posted by **Ava** on Monday, August 30, 2010 at 8:17am.

solve 4x + x(x-1)=0,

find the x-intercepts of

f(x)=4x+x(x-1)

- Algebra -
**drwls**, Monday, August 30, 2010 at 8:31amThe x(-axis) intercepts are the points on the curve where y = 0.

In this case, you can find them by solving

0 = 4x + x(x-1) = x^2 + 3x = x(x+3)

This equation is satisfied at x=0 and x=-3

The x-intercepts are therefore at

(x,y) = (-3,0) and (0,0).

- Algebra -
**MathMate**, Monday, August 30, 2010 at 8:32amThis equation can be solved by factoring:

4x + x(x-1)=0

x(4+x-1)=0

x(x+3)=0

therefore

x=0 or x+3=0

Can you take it from here?

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