Solve for P so P=?
1.)q=25-p P= I think it is 25+Q ? but am not sure
2.)Q=12-3P P= this one I get -q-12/3 but that's not aN OPTION AND i DON'T KNOW IF IT IS RIGHT OR HOW TO WRITE IT
And #3 I have no clue on ??
3.) 12Q=32-4P P=
1. P = 25 - Q
2. 3P = 12 - Q
P = 4 - Q/3
3. 4P = 32 - 12Q
P = 8 - 3Q
To solve for P in each equation, we can isolate P on one side of the equation by performing inverse operations.
1.) q = 25 - p
To isolate p, we need to get rid of the 25 on the right side. We can do this by subtracting 25 from both sides of the equation:
q - 25 = 25 - p - 25
q - 25 = -p
To isolate p, we need to change the sign of -p to p:
p = -1(q - 25)
p = -q + 25
So, P = -q + 25.
2.) Q = 12 - 3P
To isolate P, we want to get rid of the constant term 12 on the right side. We can do this by subtracting 12 from both sides of the equation:
Q - 12 = 12 - 3P - 12
Q - 12 = -3P
Next, we can divide both sides of the equation by -3 to solve for P:
(Please note that there is a minor error in your formulation, it should be -Q - 12 instead of -Q - 12/3)
P = (-Q - 12) / -3
P = (12 + Q) / 3
So, P = (12 + Q) / 3.
3.) 12Q = 32 - 4P
To isolate P, we first need to isolate -4P on the right side of the equation. We can do this by subtracting 32 from both sides:
12Q - 32 = 32 - 4P - 32
12Q - 32 = -4P
Next, we divide both sides of the equation by -4 to solve for P:
(Please note that there is a minor error in your formulation, it should be P =(-1)(12Q - 32) / -4)
P = (-1)(12Q - 32) / -4
P = (32 - 12Q) / 4
So, P = (32 - 12Q) / 4.