college physical science
posted by Richard on .
According to table 1.3, what volume of iron would be needed to balance a 1.00cm3 sample of lead on a two pan laboratory balance? Table 1.3 shows densities g/cm3 such as iron=7.87g/cm3 and lead is 11.4g/cm3
We have access to no textbook and therefore can not see table 1.3.
what time and financial constraints have you face since starting college? How did you deal with them
7.87 g/cm3 = m/ 1.00cm3
7.87g / 11.36 g/cm3
answer is 0.69 cm3
Mass/Density = Volume
_11.4_g_ = v
1.45cm3 = v
What volume of iron (density 7.87 g/cm3) would be required to balance a 1.45 cm3 sample of lead (density 11.4 g/cm3) on a two-pan laboratory balance