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November 20, 2014

November 20, 2014

Posted by **Leanna** on Sunday, August 29, 2010 at 1:49pm.

- Math AP Calc -
**Reiny**, Sunday, August 29, 2010 at 6:59pmlet the equation be

P = 357(e)^(kt) where t is the time in years since 1951

so 1981 ---> t = 30

984 = 357(e^30k)

2.756303 = e^30k

30k = ln 2.756303

k = .0337963

so now we have P = 357(e^.0337963t)

so 1000 = 357(e^.0337963t)

2.80112 = e^.0337963t

t = 30.477

30 years + .477 of the next year

30 yrs + 5.7 months

or

in the 6th month of 1951

- Math AP Calc -
**Leanna**, Sunday, August 29, 2010 at 7:33pmwouldn't it be past 1981 instead of in the 6th month of 1951?

- Math AP Calc -
**Reiny**, Sunday, August 29, 2010 at 7:38pmof course, clearly a typo. Sorry about that.

since my t=30.477 and I defined as 1951 as t=0

the time is 1951 + 30.477 = 1981 + .477yrs.

- Math AP Calc -
**Leanna**, Sunday, August 29, 2010 at 8:30pmDoes the .477 years mean the 6th month (June) you were talking about?

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