Posted by **Terry** on Sunday, August 29, 2010 at 11:36am.

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 3sin(ðt) + 5cos(ðt), where t is measured in seconds. (Round all answers to the nearest hundredth.)

(a) Find the average velocity during the time period [1, 2].

cm/s

(b) Find the average velocity during the time period [1, 1.1].

cm/s

(c) Find the average velocity during the time period [1, 1.01].

cm/s

(d) Find the average velocity during the time period [1, 1.001].

cm/s

(e) Estimate the instantaneous velocity of the particle when t = 1.

cm/s

- CALCULUS -
**Terry**, Sunday, August 29, 2010 at 11:42am
That should be sin(pi times t) not whatever symbol is up there.. sorry

- CALCULUS -
**Terry**, Sunday, August 29, 2010 at 12:20pm
Nevermind I figured it out

- CALCULUS -
**Reiny**, Sunday, August 29, 2010 at 12:27pm
a) to d) are all done the same way

I will do b)

when t=1

s = 3sin(pi) + 5 cos (pi)

= -5

when t=1.1

s = 3sin(1.1pi) + 5cos(1.1pi)

= -5.682333

average velocity = (-5.682333 - (-5))/(1.1-1)

= -6.8233

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