Posted by **Theresa** on Sunday, August 29, 2010 at 10:22am.

The table shows the position of a cyclist.

t (seconds) 0 1 2 3 4 5

s (meters) 0 1.6 4.6 10.4 17.8 25.2

(a) Find the average velocity for the time period [1, 3].

? m/s

(b) Find the average velocity for the time period [2, 3].

? m/s

(c) Find the average velocity for the time period [3, 5].

? m/s

(d) Find the average velocity for the time period [3, 4].

? m/s

Help! I have no idea where to start with this question!

- Calculus -
**drwls**, Sunday, August 29, 2010 at 10:39am
Do them all the same way.

It would e easier to see if the numbers in your table lined up one above the other.

The average velocity between time 1 (t1) and time 2 (t2) is:

(position2 - position1)/(t2 - t1)

The first answer is

(10.4 - 1.6)/(3 -1) = 3.25 m/s

- Calculus -
**Theresa**, Sunday, August 29, 2010 at 10:44am
Thank you! I was trying to make it harder than it really was! lol! Thank you again!

- Calculus -
**Anonymous**, Thursday, September 17, 2015 at 1:09am
how do i find the instaneous velocity at t=

3

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