Calculus
posted by Theresa on .
The table shows the position of a cyclist.
t (seconds) 0 1 2 3 4 5
s (meters) 0 1.6 4.6 10.4 17.8 25.2
(a) Find the average velocity for the time period [1, 3].
? m/s
(b) Find the average velocity for the time period [2, 3].
? m/s
(c) Find the average velocity for the time period [3, 5].
? m/s
(d) Find the average velocity for the time period [3, 4].
? m/s
Help! I have no idea where to start with this question!

Do them all the same way.
It would e easier to see if the numbers in your table lined up one above the other.
The average velocity between time 1 (t1) and time 2 (t2) is:
(position2  position1)/(t2  t1)
The first answer is
(10.4  1.6)/(3 1) = 3.25 m/s 
Thank you! I was trying to make it harder than it really was! lol! Thank you again!

how do i find the instaneous velocity at t=
3