geometry
posted by mic on .
how do you solve for x and y?
3x2(y+2)=6
4(x+1)y=7

3x2y4=6
3x2y=2*
4x+4y=7
4xy=3*
So your 2 new equations are
3x2y=2
4xy=3
Multiply the bottom equation by 2 to cancel the y's gives us
8x+2y=6
3x2y=2
5x=4
x=4/5
Plug the x value into either of your "2 new equations above" to figure out y.