Saturday

August 30, 2014

August 30, 2014

Posted by **jin** on Saturday, August 28, 2010 at 1:49am.

Let f(x)=(x )^(1/3). The linear approximation to f(x) at x=8 can be written in the form y=mx+b where m is: and where b is:

Using this, we find our approximation for (8.4)^(1/3) is

- calculus -
**Damon**, Saturday, August 28, 2010 at 9:16amy = x^(1/3)

dy/dx = (1/3) x^-(1/3)

at x = 8

y(8) = 2

dy/dx = (1/3)/2

y(x+h) = y(x) + h dy/dx

y(8.4) = 2 + .4 (1/3)/2

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