Posted by jin on Saturday, August 28, 2010 at 1:25am.
The relative error in area is, to first approximation, twice the relative error in a linear dimension.
That is because
(delta A)/A = (1 + epsilon)^2 - 1
= 1 + 2 epsilon + epsilon^2 - 1
= 2 epsilon
when epsilon << 1
In your case, the answer is
2*0.5/78 = 1/78 = 1.3%
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