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March 28, 2017

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the perimeter of a rectangle is 112 inches. The length exceeds the width by 50 inches and width.

  • Algebra - ,

    please someone help it is due tonight I have tried all I know how to figure it out

  • Algebra - ,

    Let w=width
    Length=w+50
    Permeter=2(length+width)
    =2(w+50+w)

    Solve for w in
    2(w+50+w)=112

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