Posted by **kwack** on Friday, August 27, 2010 at 6:54pm.

The altitude of a triangle is increasing at a rate of 1500 centimeters/minute while the area of the triangle is increasing at a rate of 1000 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10000 centimeters and the area is 99000 square centimeters?

- math -
**drwls**, Friday, August 27, 2010 at 10:29pm
This is a calculus problem.

When the altitude H is 1000 and the area A is 99000, the base width is

B = 2A/B =2*99,000/ 10,000 = 198 cm

A = (1/2)*altitude*base = H*B/2

dA/dt = (1/2)[H*dB/dt + B*dH/dt]

1000 = (1/2)[1000*dB/dt + 198*1500]

solve for dB/dt in cm per minute

1000 = (1/2)[10,000dB/dt + 198*dH/dt]

- math -
**jin**, Saturday, August 28, 2010 at 12:09am
for dB/dt, i got -295 is that correct?

so i just plug it in to find dH/dt?

## Answer this Question

## Related Questions

Math calculus - The altitude of a triangle is increasing at a rate of 1000 ...

Calculus - The altitude of a triangle is increasing at a rate of 3000 ...

Math - The altitude of a triangle is increasing at a rate of 2500 centimeters/...

CAL - The altitude of a triangle is increasing at a rate of 2500 centimeters/...

CAL - The altitude of a triangle is increasing at a rate of 2500 centimeters/...

Calculus Please help! - The altitude of a triangle is increasing at a rate of ...

Calc - The altitude of a triangle is increasing at a rate of 2500 centimeters/...

calculus - The altitude of a triangle is increasing at a rate of 3.000 ...

math - The altitude of a triangle is increasing at a rate of 3 centimeters/...

math - The altitude of a triangle is increasing at a rate of 1.500 centimeters/...