Find three consecutive even integers whose sum is 60.
You're on the right track.
Try 18, 20, 22
Hint:
60/3 = ?
To find three consecutive even integers whose sum is 60, follow these steps:
Step 1: Let's assume the first even integer as x.
Step 2: Since the next two integers are consecutive, the second even integer will be (x + 2), and the third even integer will be (x + 4).
Step 3: Add the three integers together: x + (x + 2) + (x + 4) = 60.
Step 4: Simplify the equation: 3x + 6 = 60.
Step 5: Subtract 6 from both sides of the equation: 3x = 54.
Step 6: Divide both sides of the equation by 3: x = 18.
Step 7: Now, substitute the value of x back into the equation to find the other two integers: 18 + 2 = 20, and 18 + 4 = 22.
Therefore, the three consecutive even integers that sum up to 60 are 18, 20, and 22.