Divide:
(25b^3+5b^2+34b+29)/(5b+3)
You would use long division for polynomials, very similar to the long division for numbers.
Each digit in the long division will be replaced by the coefficient of the powers of b.
(25b^3+5b^2+34b+29)
Dividing by 5b+3,
gives the first "digit" of the quotient as 5b²
and 5b²*3=15b²
Subtract 25b³+15b² from the original expression gives an expression one degree lower:
(25b^3+5b^2+34b+29) - 25b³+15b²
=-10b²+34b+29
Continuing this way will give the complete quotient.
See for reference:
http://www.sosmath.com/algebra/factor/fac01/fac01.html
25b^3+5b^2+34b+29
go to webmathcom, click algebra and under simplifying expressions click anything else and enter your promblem and hit try to simplify it and it will explain everything
Your webpage did a lousy job of the problem,
your answer is not correct, it is simply the original numerator.
(How can the exponent of the first term stay the same ?????)
To divide the polynomial (25b^3 + 5b^2 + 34b + 29) by (5b + 3), you can use the long division method. Here's how you can do it step by step:
1. Start by dividing the first term of the dividend, which is 25b^3, by the first term of the divisor, which is 5b. The result is 5b^2. Write this as the first term of the quotient.
5b^2
__________
5b + 3 | 25b^3 + 5b^2 + 34b + 29
2. Multiply the entire divisor (5b + 3) by the term you just found in the quotient (5b^2). The result is 25b^3 + 15b^2. Write this under the dividend, and subtract it from the original dividend.
5b^2
__________
5b + 3 | 25b^3 + 5b^2 + 34b + 29
-(25b^3 + 15b^2)
_______________________
- 10b^2 + 34b + 29
3. Bring down the next term from the dividend, which is 34b, and continue the process.
5b^2 + ( -10b )
____________________
5b + 3 | 25b^3 + 5b^2 + 34b + 29
-(25b^3 + 15b^2)
_______________________
- 10b^2 + 34b + 29
-( -10b^2 + 6b )
______________
28b + 29
4. Now, bring down the last term from the original dividend, which is 29.
5b^2 - 10b + 28
___________________
5b + 3 | 25b^3 + 5b^2 + 34b + 29
-(25b^3 + 15b^2)
_______________________
- 10b^2 + 34b + 29
-( -10b^2 + 6b )
______________
28b + 29
-( 28b + 9 )
___________
20
5. At this point, there is no remainder left. The result of the division is the quotient you obtained: 5b^2 - 10b + 28.
Therefore, the polynomial division of (25b^3 + 5b^2 + 34b + 29) by (5b + 3) results in a quotient of 5b^2 - 10b + 28 and no remainder.