Posted by Kailey on Thursday, August 26, 2010 at 11:27pm.
The pin head's volume is
V = (pi/6*D^3 = 0.5*10^3 mm^3
= 0.5*10^-3 cm^3.
Assume the pin is steel. The density is about 8 g/cm^3 and the pinhead mass is 4*10^-3 g. The mean molecular mass of the most abundant metal in the steel (iron) is 56 g/mole, so there are
4*10^-3/56 = 7*10^-5 moles in the pinhead. Multiply that by Avogadro's number for the number of atoms.
I get 4*10^19
Your nearest estimate to that is #2. (10^19)
10^14.
Divide area of pinhead by area of atom
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