Posted by **Amy~** on Thursday, August 26, 2010 at 10:36pm.

What would be the steps to solving this problem?

The aluminum sulfate hydrate [Al2(SO4)3 (times) xH2O] contains 8.20 % Al by mass. Calculate x, that is , the number of water molecules associated with each Al2(SO4)3 unit.

- Chemistry -
**MathMate**, Thursday, August 26, 2010 at 11:29pm
RMM for Al2(SO4)3

=27*2+(32+4*16)*3

=342

RMM for H2O

=2+16

=18

Number of water molecules = n

Thus

27*2/(342+18n)=0.082

Solve for n to get 18 (to 2 signinficant digits).

- Chemistry -
**Amy~**, Thursday, August 26, 2010 at 11:43pm
Thank You so much!

I have some other questions that I don't understand.

## Answer This Question

## Related Questions

- chemistry - A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 ยท 18 H2O, ...
- Chemistry - How many grams of aluminum sulfate, Al2( SO4)3 , will be formed from...
- Chemistry.... - Wouldn't it be 3*0.234 instead of 2* 0.234? since....2Al3+ +...
- chemistry - Hi, the question is: in each reaction, identify what have been ...
- science (chem) - consider the fo9rmula for Al2(SO4)3,which is used in ...
- chemistry - Al(s) + H2SO4(aq)-> Al2(SO4)3(aq) + H2(g) Consider the unbalanced...
- science - I need help to find the answer to this problem: The formula for ...
- chemistry - In a solution of Al2(SO4)3 the Al3+ concentration is .12 M. What ...
- Chemistry - A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the ...
- chemestiry - Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the ...

More Related Questions