1/5(b+10)-7=1/3(b+9)

I'm assuming the (b + 10) and the

(b + 9) terms are in the numerator.

(b + 10)/5 - 7 = (b + 9)/3
Multiply each side by 15:
3(b + 10) - 105 = 5(b + 9)
3(b + 10) - 5(b + 9) = 105
3b + 30 - 5b - 45 = 105
3b - 5b = 105 - 30 + 45
-2b = 120
b = -60.