Posted by **ami** on Thursday, August 26, 2010 at 3:37pm.

A stone is dropped from the top of a cliff. It hits the ground below after 3.10 s. How high is the cliff?

- physics -
**drwls**, Thursday, August 26, 2010 at 4:59pm
If H is the distance fallen in time t,

H = (g/2) t^2

Set t = 3.10 s and solve for H.

g is the acceleration of gravity, 9.8 m/s^2

- physics -
**anonymous**, Wednesday, October 10, 2012 at 11:39pm
3.10 x 9.8=30.38

30.38^2=922.9444

922.9444/9.8^2

922.9444/19.6= 47.0m

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