Posted by ami on Thursday, August 26, 2010 at 3:37pm.
A stone is dropped from the top of a cliff. It hits the ground below after 3.10 s. How high is the cliff?

physics  drwls, Thursday, August 26, 2010 at 4:59pm
If H is the distance fallen in time t,
H = (g/2) t^2
Set t = 3.10 s and solve for H.
g is the acceleration of gravity, 9.8 m/s^2

physics  anonymous, Wednesday, October 10, 2012 at 11:39pm
3.10 x 9.8=30.38
30.38^2=922.9444
922.9444/9.8^2
922.9444/19.6= 47.0m
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