It is estimated that each cigarette a person smokes shortens that person's life by the amount of time she or he took to smoke it plus ten minutes. Write an algebraic rule that determines the number of minutes (t) a person's life is shortened by smoking c cigarettes per day for y years if we assume each cigarette takes about five minutes to smoke. If a person smokes 20 cigarettes per day for 10 years by how much has that person's life been shortened?
I just don't know where to start, if someone could help me start I could probably finish it.
So in effect the person loses 15 minutes for each cigarette smoked.
so in one year he/she would lose 365(15)c minutes
so in y years, he/she would lose 365(15)cy minutes
T = 5475cy minutes
for c=20, y=10
T = 5475(20)(10) minutes = 1095000minutes.
divide by 60 to get hours
divide by 24 to get days, etc.