February 23, 2017

Homework Help: calculus

Posted by Douglas on Wednesday, August 25, 2010 at 10:29pm.

The problem is to evaluate the integral 10secxtanx dx, from -1/7 pi to 3/8 pi.

What I've done so far is evaluated the integral since secxtanx is a trig identity, so the integral of that is secx. I took out the 10 since it was a constant which leaves me with 10[sec(3/8)pi - sec(-1/7)pi]. Since those values aren't part of the unit circle, I put that in my calculator and came up with the answer 15.03209666, however the program that has my question is not accepting this answer. My calculator is in radians.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions