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July 30, 2015

Homework Help: calculus

Posted by Douglas on Wednesday, August 25, 2010 at 10:29pm.

The problem is to evaluate the integral 10secxtanx dx, from -1/7 pi to 3/8 pi.

What I've done so far is evaluated the integral since secxtanx is a trig identity, so the integral of that is secx. I took out the 10 since it was a constant which leaves me with 10[sec(3/8)pi - sec(-1/7)pi]. Since those values aren't part of the unit circle, I put that in my calculator and came up with the answer 15.03209666, however the program that has my question is not accepting this answer. My calculator is in radians.

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