Posted by NENE on Wednesday, August 25, 2010 at 9:02pm.
Two spheres are launched horizontally from a 1.1m high table. Sphere A is launched with an initial speed of 5.0M/S . Sphere B is launched with an initial speed of 3.0M/S
A. What is the time for the sphere A to hit the floor? and sphere B to hit the ground
B. What is the distance that sphere A travels from the edge of the table? And what is the distance for sphere B travels from edge of the table??

PHYSICS  drwls, Wednesday, August 25, 2010 at 10:00pm
Since they are both launched horizontally, there is zero initial vertical velocity component in each case and the times that they take to hit the ground are the same.
That time T can be obtained by solving
(g/2) T^2 = 1.1 m
The horizontal distance travaled when they hit the ground is Vo*T
Vo = 3.0 or 5.0 m/s

PHYSICS  NENE, Wednesday, August 25, 2010 at 10:37pm
the second question is very tricky. can you please give me the equation to use to find the distance??

PHYSICS  NENE, Wednesday, August 25, 2010 at 10:50pm
i got the answer. thanks
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