Posted by NENE on Wednesday, August 25, 2010 at 9:02pm.
Since they are both launched horizontally, there is zero initial vertical velocity component in each case and the times that they take to hit the ground are the same.
That time T can be obtained by solving
(g/2) T^2 = 1.1 m
The horizontal distance travaled when they hit the ground is Vo*T
Vo = 3.0 or 5.0 m/s
the second question is very tricky. can you please give me the equation to use to find the distance??
i got the answer. thanks
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