Posted by lindsey on Wednesday, August 25, 2010 at 6:44pm.
The sum of three consecutive odd integers is
S(n)=(n-2) + n + (n+2) = 3n
So 54<S(n)<63, or
54 < 3n < 63
Divide all by 3 to get
18 < n < 21
Solve for all valid (integer) value of n.
Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.
how do you get n-2, n, n+2 I keep getting n, n+2 and n+4?
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