Posted by **lindsey** on Wednesday, August 25, 2010 at 6:44pm.

find all sets of three consecutive odd integers whose sum is greater than 54 and less than 63

- trig -
**MathMate**, Wednesday, August 25, 2010 at 7:31pm
The sum of three consecutive odd integers is

S(n)=(n-2) + n + (n+2) = 3n

So 54<S(n)<63, or

54 < 3n < 63

Divide all by 3 to get

18 < n < 21

Solve for all valid (integer) value of n.

Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.

- trig -
**lindsey**, Wednesday, August 25, 2010 at 7:40pm
how do you get n-2, n, n+2 I keep getting n, n+2 and n+4?

## Answer this Question

## Related Questions

- algebra - Find all sets of two consecutive positive odd integers whose sum is ...
- algebra - Find all sets of two consecutive positive odd integers whose sum is ...
- Algebra 2 - Find three consecutive odd integers whose sum is less than 20 but ...
- math - A. Four times one odd integer is 14 less than three times the next even ...
- maths - 1. If the first and third of three consecutive odd integers are added, ...
- math - Find three consecutive odd integers whose sum is -33.
- algebra - Twice the greater of two consecutive odd integers is 13 less than ...
- math - Twice the greater of two consecutive odd integers is 13 less than three ...
- math check - Posted by TchrWill on Thursday, July 14, 2005 at 5:44pm. 2.)The sum...
- Algebra - The sum of the squares of the largest and smallest of three ...