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April 18, 2014

April 18, 2014

Posted by **lindsey** on Wednesday, August 25, 2010 at 6:44pm.

- trig -
**MathMate**, Wednesday, August 25, 2010 at 7:31pmThe sum of three consecutive odd integers is

S(n)=(n-2) + n + (n+2) = 3n

So 54<S(n)<63, or

54 < 3n < 63

Divide all by 3 to get

18 < n < 21

Solve for all valid (integer) value of n.

Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.

- trig -
**lindsey**, Wednesday, August 25, 2010 at 7:40pmhow do you get n-2, n, n+2 I keep getting n, n+2 and n+4?

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