high school algerbra class
posted by kenneth on .
someone please show me how to work this problem with the steps, so I can see if I can get it. This is due tomorrow in class. Thank you.
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The parentheses that have been added do not help, because they are implicit with the rules of priorities of multiplication/division over addition/subtraction.
If the original problem is a fraction with a denominator of 2 and x²-4 as the denominator, you need to insert parentheses around all numerators and denominators that contain more than one term.
2/x²-4 = (2/x²) - 4
2/(x²-4) = 2/((x+2)(x-2))
Your expression as is translates to:
=(2/x²) - 3 + (3/x²) + x - 6 + (1/x) + 3
which I doubt is the same that was printed in the book.