Posted by kenneth on .
(2/x^24)+(3/x^2)+(x6+1/x+3)
someone please show me how to work this problem with the steps, so I can see if I can get it. This is due tomorrow in class. Thank you.

high school algerbra class 
MathMate,
See comments at:
http://www.jiskha.com/display.cgi?id=1282707251
The parentheses that have been added do not help, because they are implicit with the rules of priorities of multiplication/division over addition/subtraction.
If the original problem is a fraction with a denominator of 2 and x²4 as the denominator, you need to insert parentheses around all numerators and denominators that contain more than one term.
2/x²4 = (2/x²)  4
while
2/(x²4) = 2/((x+2)(x2))
Your expression as is translates to:
(2/x^24)+(3/x^2)+(x6+1/x+3)
=(2/x²)  3 + (3/x²) + x  6 + (1/x) + 3
which I doubt is the same that was printed in the book.