Posted by Jeffrey on .
Assuming the density of a 5% acetic acid solution is 1.0 g/mL,determine the volume of the acetic acid solution necessary toneutralize 25.0 mL of 0.10M NaOH.
L x M = moles NaOH used.
moles acetic acid = moles NaOH
g acetic acid = moles x molar mass.
1 g/cc x #cc x 0.05 = grams acetic acid.
Solve for #cc.
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