Tuesday

July 22, 2014

July 22, 2014

Posted by **Chris** on Wednesday, August 25, 2010 at 5:06am.

- Physics -
**drwls**, Wednesday, August 25, 2010 at 5:59amIn the United States,

"physical education" is the class devoted to exercise, fitness and sports. Your question is about physics.

Starting at t=0 when the first body is thrown, the height is

Y1 = 98t - 4.9 t^2. The second body's height, measured from the same t, is

Y2 = 98(t-4) - 4.9 (t-4)^2 (t>4)

Set the two equal and solve for t.

98t - 4.9 t^2 = 98(t-4) - 4.9 (t-4)^2

0 = -392 +4.9(8t)-16*4.9

39.2 t = 392 + 78.4 = 470.4

t = 12.0 seconds

The height at that time, for both objects, is 470.4 m

**Related Questions**

Algebra 2 - If an object is thrown vertically upward with an initial velocity of...

Dynamics - A ball is thrown vertically upward with a velocities of 18 m/s. Two ...

math - A ball is thrown vertically upward with a velocities of 18 m/s. Two ...

BTech, Mechanical - A ball is thrown vertically upward with velocities of 18 m/s...

physics - An object is projected vertically upwards with a velocity of 28m/s. ...

science - If Two bodies of same mass is thrown from top of a tower with same ...

Algebra 2 - if an object is thrown vertically upward with an initial velocity of...

physics - A mass is dropped from a height of 30m, and at the same time from ...

Algebra 2 - If an object is thrown vertically upward with an initial velocity of...

Algebra - If an object is thrown vertically upward with an initial velocity of ...