The density of sea water is slightly higher than that of fresh water. The higher density is due to the fact that sea water contains salts such as sodium choride and magnesium chloride. Suppose you have a container that holds 5.00 kg of freshwater, which has a density of 1.00 g/cubic cm. If 5.00 kg of sea water with a density of 1.033 g/cubic cm is placed in a container of the same size, what is the volume of that space that is left unfilled? Not just an answer, I want to know how to do this, please!

Vf = 5000 g / (1 g/cm^3

Vs = 5000g / (1.033 g/cm^3)

we want Vf - Vs

Oh, I have the same question on my homework. Hm, I don't know either.

To find the volume of the space that is left unfilled, we need to calculate the difference in volume between the freshwater and the sea water.

To start, we can use the equation for density:

Density = Mass / Volume

Given information:
Mass of freshwater = 5.00 kg
Density of freshwater = 1.00 g/cm³

To convert the mass of freshwater to grams, we can use the conversion factor: 1 kg = 1000 g.

So, the mass of freshwater in grams = 5.00 kg * 1000 g/kg = 5000 g.

Now, let's rearrange the density equation to solve for volume:

Volume = Mass / Density

Calculating the volume of freshwater:

Volume of freshwater = Mass of freshwater / Density of freshwater
= 5000 g / 1.00 g/cm³
= 5000 cm³

Now, let's find the volume of sea water.

Given information:
Mass of sea water = 5.00 kg
Density of sea water = 1.033 g/cm³

Similarly converting the mass of sea water to grams:

Mass of sea water in grams = 5.00 kg * 1000 g/kg = 5000 g

Calculating the volume of sea water:

Volume of sea water = Mass of sea water / Density of sea water
= 5000 g / 1.033 g/cm³
≈ 4834 cm³

Finally, to find the volume of the space that is left unfilled:

Volume unfilled = Volume of freshwater - Volume of sea water
= 5000 cm³ - 4834 cm³
= 166 cm³

So, the volume of the space that is left unfilled is approximately 166 cubic centimeters.