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November 23, 2014

November 23, 2014

Posted by **anonymous** on Tuesday, August 24, 2010 at 4:15pm.

"Come up with a number. Add 3 to it. Muliply by 1 more than the original number. Subtract 3. Divide by the original number. Subtract 4. You should get the original number.

How it works: x is the original number. Add 3 to x to get (x+3). Multiply by (x+1) to get x² + 4x + 3. Subtract 3 to get x² + 4x, which factorises to x(x+4). Dividing by the original number, x, gives x + 4, and subtracting 4 gives the original number, x."

- Algebra -
**anonymous**, Tuesday, August 24, 2010 at 4:24pmIs (x^2+4x/x)-4 correct?

- Algebra -
**Reiny**, Tuesday, August 24, 2010 at 5:04pmCome up with a number: x

Add 3 to it : x+3

Muliply by 1 more than the original number : (x+3)(x+1)

Subtract 3 : (x+3)(x+1) - 3

Divide by the original number : [(x+3)(x+1) - 3]/x

Subtract 4 : [(x+3)(x+1) - 3]/x - 4

**[(x+3)(x+1) - 3]/x - 4**

= (x^2 + 4x +3 - 3)/x - 4

= (x^2 + 4x)/x - 4

= x + 4 - 4

= x

Notice the long expression follows the actual wording.

Your answer of (x^2+4x/x)-4 needs brackets like this:

(x^2+4x)/x - 4 or else only the 4x is divided by x

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