Post a New Question

Math

posted by .

A man left his property to his wife, his son, his daughter, and his sister. His son and daughter got half of the property, sharing in the ratio of 4 to 3. His wife got twice as much as the daughter. If his sister received $15,000, what was the value of all of his property?

  • Math -

    Son and daughter got half, in the ratio of 4 to three.
    So
    son+daughter = 1/2
    son got 4/14
    daughter got 3/14

    Wife got twice as the daughter = 6/14

    Sister got 1-(4/14+3/14+6/14) = 1/14

    If 1/14 of the property was worth $15,000, the value of his estate is
    $15,000/(1/14) =?

  • Math -

    Daughter's share = x-dollars.
    Wife's share = 2x-dollars.
    Son's share = 4x/3-dollars.
    Sister's share = 15000 dollars.

    The son and daughter received 1/2 of
    the property. The other 1/2 went to the
    wife and sister:

    x + 4x/3 = V/2 = 2x + 15000,
    x + 4x/3 = 2x + 15000,
    Solve for x:
    x = 45000 = Daughter's share,
    2x = 2 * 45000 = 90000 = Wife's share,
    4x/3 = 4*45000/3 = 60000 = son's share

    V/2 = 2 * 45000 + 15000 = 105000,
    V = 210000 = Value of property.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question